Base | Representation |
---|---|
bin | 1110110111011111100… |
… | …0011001101010000011 |
3 | 220102021021011001020111 |
4 | 3231313320121222003 |
5 | 13141042033004243 |
6 | 313200303452151 |
7 | 24311256051115 |
oct | 3556770315203 |
9 | 812237131214 |
10 | 255414344323 |
11 | 99358814286 |
12 | 416018b7057 |
13 | 1b115a12128 |
14 | c50d92d3b5 |
15 | 699d31939d |
hex | 3b77e19a83 |
255414344323 has 2 divisors, whose sum is σ = 255414344324. Its totient is φ = 255414344322.
The previous prime is 255414344309. The next prime is 255414344327. The reversal of 255414344323 is 323443414552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255414344323 - 213 = 255414336131 is a prime.
It is not a weakly prime, because it can be changed into another prime (255414344327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127707172161 + 127707172162.
It is an arithmetic number, because the mean of its divisors is an integer number (127707172162).
Almost surely, 2255414344323 is an apocalyptic number.
255414344323 is a deficient number, since it is larger than the sum of its proper divisors (1).
255414344323 is an equidigital number, since it uses as much as digits as its factorization.
255414344323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 691200, while the sum is 40.
Adding to 255414344323 its reverse (323443414552), we get a palindrome (578857758875).
The spelling of 255414344323 in words is "two hundred fifty-five billion, four hundred fourteen million, three hundred forty-four thousand, three hundred twenty-three".
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