Base | Representation |
---|---|
bin | 1110110111100110011… |
… | …1010010100010001001 |
3 | 220102100021211220010221 |
4 | 3231321213102202021 |
5 | 13141122003210004 |
6 | 313203222510041 |
7 | 24312061120612 |
oct | 3557147224211 |
9 | 812307756127 |
10 | 255443413129 |
11 | 99373169093 |
12 | 4160b595321 |
13 | 1b11ba4c2c8 |
14 | c513738c09 |
15 | 69a0b5c354 |
hex | 3b799d2889 |
255443413129 has 2 divisors, whose sum is σ = 255443413130. Its totient is φ = 255443413128.
The previous prime is 255443413103. The next prime is 255443413171. The reversal of 255443413129 is 921314344552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 241336387600 + 14107025529 = 491260^2 + 118773^2 .
It is a cyclic number.
It is not a de Polignac number, because 255443413129 - 217 = 255443282057 is a prime.
It is not a weakly prime, because it can be changed into another prime (255443413829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127721706564 + 127721706565.
It is an arithmetic number, because the mean of its divisors is an integer number (127721706565).
Almost surely, 2255443413129 is an apocalyptic number.
It is an amenable number.
255443413129 is a deficient number, since it is larger than the sum of its proper divisors (1).
255443413129 is an equidigital number, since it uses as much as digits as its factorization.
255443413129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 518400, while the sum is 43.
The spelling of 255443413129 in words is "two hundred fifty-five billion, four hundred forty-three million, four hundred thirteen thousand, one hundred twenty-nine".
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