Base | Representation |
---|---|
bin | 1110110111110100000… |
… | …0011101000010011011 |
3 | 220102111020222011001112 |
4 | 3231331000131002123 |
5 | 13141231041411103 |
6 | 313213015010535 |
7 | 24313352032346 |
oct | 3557500350233 |
9 | 812436864045 |
10 | 255500341403 |
11 | 993a231114a |
12 | 41626669a4b |
13 | 1b12a792088 |
14 | c51b11745d |
15 | 69a5b54cd8 |
hex | 3b7d01d09b |
255500341403 has 4 divisors (see below), whose sum is σ = 255530062800. Its totient is φ = 255470620008.
The previous prime is 255500341387. The next prime is 255500341409. The reversal of 255500341403 is 304143005552.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 255500341403 - 24 = 255500341387 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 255500341403.
It is not an unprimeable number, because it can be changed into a prime (255500341409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14847800 + ... + 14864997.
It is an arithmetic number, because the mean of its divisors is an integer number (63882515700).
Almost surely, 2255500341403 is an apocalyptic number.
255500341403 is a deficient number, since it is larger than the sum of its proper divisors (29721397).
255500341403 is an equidigital number, since it uses as much as digits as its factorization.
255500341403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29721396.
The product of its (nonzero) digits is 36000, while the sum is 32.
Adding to 255500341403 its reverse (304143005552), we get a palindrome (559643346955).
The spelling of 255500341403 in words is "two hundred fifty-five billion, five hundred million, three hundred forty-one thousand, four hundred three".
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