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2555320211449 is a prime number
BaseRepresentation
bin100101001011110100111…
…101000001011111111001
3100001021201122210110220221
4211023310331001133321
5313331243433231244
65233521540220041
7352421134263625
oct45136475013771
910037648713827
102555320211449
118a57837079a5
123532a369a621
13156c72736c75
148b96cc1a185
154670a5ae784
hex252f4f417f9

2555320211449 has 2 divisors, whose sum is σ = 2555320211450. Its totient is φ = 2555320211448.

The previous prime is 2555320211399. The next prime is 2555320211453. The reversal of 2555320211449 is 9441120235552.

2555320211449 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2303923265424 + 251396946025 = 1517868^2 + 501395^2 .

It is a cyclic number.

It is not a de Polignac number, because 2555320211449 - 235 = 2520960473081 is a prime.

It is a super-2 number, since 2×25553202114492 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2555320911449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277660105724 + 1277660105725.

It is an arithmetic number, because the mean of its divisors is an integer number (1277660105725).

Almost surely, 22555320211449 is an apocalyptic number.

It is an amenable number.

2555320211449 is a deficient number, since it is larger than the sum of its proper divisors (1).

2555320211449 is an equidigital number, since it uses as much as digits as its factorization.

2555320211449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 43.

The spelling of 2555320211449 in words is "two trillion, five hundred fifty-five billion, three hundred twenty million, two hundred eleven thousand, four hundred forty-nine".