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2556011113 = 14917154437
BaseRepresentation
bin1001100001011001…
…1010001001101001
320121010120211002021
42120112122021221
520213314323423
61101344104441
7120224510305
oct23026321151
96533524067
102556011113
1110a188aa87
125b4005121
13319710916
141a3670d05
15ee5e195d
hex9859a269

2556011113 has 4 divisors (see below), whose sum is σ = 2573165700. Its totient is φ = 2538856528.

The previous prime is 2556011089. The next prime is 2556011131. The reversal of 2556011113 is 3111106552.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1427857369 + 1128153744 = 37787^2 + 33588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2556011113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2556011713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8577070 + ... + 8577367.

It is an arithmetic number, because the mean of its divisors is an integer number (643291425).

Almost surely, 22556011113 is an apocalyptic number.

It is an amenable number.

2556011113 is a deficient number, since it is larger than the sum of its proper divisors (17154587).

2556011113 is a wasteful number, since it uses less digits than its factorization.

2556011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17154586.

The product of its (nonzero) digits is 900, while the sum is 25.

The square root of 2556011113 is about 50557.0085448101. The cubic root of 2556011113 is about 1367.2698774896.

Adding to 2556011113 its reverse (3111106552), we get a palindrome (5667117665).

The spelling of 2556011113 in words is "two billion, five hundred fifty-six million, eleven thousand, one hundred thirteen".

Divisors: 1 149 17154437 2556011113