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2556121433 = 191012415527
BaseRepresentation
bin1001100001011011…
…0101000101011001
320121010210102102012
42120112311011121
520213331341213
61101350315305
7120225450035
oct23026650531
96533712365
102556121433
1110a1955958
125b4058b35
1331974bbb8
141a369d1c5
15ee6144a8
hex985b5159

2556121433 has 16 divisors (see below), whose sum is σ = 2729063040. Its totient is φ = 2387232000.

The previous prime is 2556121429. The next prime is 2556121453. The reversal of 2556121433 is 3341216552.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 2556121433 - 22 = 2556121429 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2556121433.

It is not an unprimeable number, because it can be changed into a prime (2556121453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 459716 + ... + 465242.

It is an arithmetic number, because the mean of its divisors is an integer number (170566440).

Almost surely, 22556121433 is an apocalyptic number.

It is an amenable number.

2556121433 is a deficient number, since it is larger than the sum of its proper divisors (172941607).

2556121433 is a wasteful number, since it uses less digits than its factorization.

2556121433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5888.

The product of its digits is 21600, while the sum is 32.

The square root of 2556121433 is about 50558.0995786036. The cubic root of 2556121433 is about 1367.2895481191.

Adding to 2556121433 its reverse (3341216552), we get a palindrome (5897337985).

The spelling of 2556121433 in words is "two billion, five hundred fifty-six million, one hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 19 101 241 1919 4579 5527 24341 105013 462479 558227 1332007 10606313 25308133 134532707 2556121433