Base | Representation |
---|---|
bin | 100101001100100111100… |
… | …011001101101110101001 |
3 | 100001100220211002122220021 |
4 | 211030213203031232221 |
5 | 313340013241140232 |
6 | 5234142102400441 |
7 | 352451152500316 |
oct | 45144743155651 |
9 | 10040824078807 |
10 | 2556169083817 |
11 | 8a6079899308 |
12 | 35349ba30121 |
13 | 15707956bbcb |
14 | 8ba0d867d0d |
15 | 46759d8c397 |
hex | 253278cdba9 |
2556169083817 has 2 divisors, whose sum is σ = 2556169083818. Its totient is φ = 2556169083816.
The previous prime is 2556169083683. The next prime is 2556169083869. The reversal of 2556169083817 is 7183809616552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1992222154521 + 563946929296 = 1411461^2 + 750964^2 .
It is a cyclic number.
It is not a de Polignac number, because 2556169083817 - 227 = 2556034866089 is a prime.
It is a super-3 number, since 3×25561690838173 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2556169083217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278084541908 + 1278084541909.
It is an arithmetic number, because the mean of its divisors is an integer number (1278084541909).
Almost surely, 22556169083817 is an apocalyptic number.
It is an amenable number.
2556169083817 is a deficient number, since it is larger than the sum of its proper divisors (1).
2556169083817 is an equidigital number, since it uses as much as digits as its factorization.
2556169083817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21772800, while the sum is 61.
The spelling of 2556169083817 in words is "two trillion, five hundred fifty-six billion, one hundred sixty-nine million, eighty-three thousand, eight hundred seventeen".
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