Base | Representation |
---|---|
bin | 111010001000000011011101… |
… | …000000011011011110000011 |
3 | 1020112010221221101101201100212 |
4 | 322020003131000123132003 |
5 | 232001402022300211141 |
6 | 2303411245134304335 |
7 | 104563251340256624 |
oct | 7210033500333603 |
9 | 1215127841351325 |
10 | 255640161335171 |
11 | 74500424603a88 |
12 | 248089389580ab |
13 | ac849c1023262 |
14 | 471b09aa21a4b |
15 | 1e84bc1ee32eb |
hex | e880dd01b783 |
255640161335171 has 2 divisors, whose sum is σ = 255640161335172. Its totient is φ = 255640161335170.
The previous prime is 255640161335123. The next prime is 255640161335191. The reversal of 255640161335171 is 171533161046552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255640161335171 - 242 = 251242114824067 is a prime.
It is not a weakly prime, because it can be changed into another prime (255640161335191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127820080667585 + 127820080667586.
It is an arithmetic number, because the mean of its divisors is an integer number (127820080667586).
Almost surely, 2255640161335171 is an apocalyptic number.
255640161335171 is a deficient number, since it is larger than the sum of its proper divisors (1).
255640161335171 is an equidigital number, since it uses as much as digits as its factorization.
255640161335171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268000, while the sum is 50.
The spelling of 255640161335171 in words is "two hundred fifty-five trillion, six hundred forty billion, one hundred sixty-one million, three hundred thirty-five thousand, one hundred seventy-one".
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