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2556433001 is a prime number
BaseRepresentation
bin1001100001100000…
…0001001001101001
320121011101020210202
42120120001021221
520213421324001
61101401121545
7120231215303
oct23030011151
96534336722
102556433001
1110a2048a51
125b41892b5
1331982a965
141a3740973
15ee67696b
hex98601269

2556433001 has 2 divisors, whose sum is σ = 2556433002. Its totient is φ = 2556433000.

The previous prime is 2556432997. The next prime is 2556433037. The reversal of 2556433001 is 1003346552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1951518976 + 604914025 = 44176^2 + 24595^2 .

It is a cyclic number.

It is not a de Polignac number, because 2556433001 - 22 = 2556432997 is a prime.

It is not a weakly prime, because it can be changed into another prime (2556433801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278216500 + 1278216501.

It is an arithmetic number, because the mean of its divisors is an integer number (1278216501).

Almost surely, 22556433001 is an apocalyptic number.

It is an amenable number.

2556433001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2556433001 is an equidigital number, since it uses as much as digits as its factorization.

2556433001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

The square root of 2556433001 is about 50561.1807714179. The cubic root of 2556433001 is about 1367.3450992570.

Adding to 2556433001 its reverse (1003346552), we get a palindrome (3559779553).

The spelling of 2556433001 in words is "two billion, five hundred fifty-six million, four hundred thirty-three thousand, one".