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2556944724853 = 9419271466687
BaseRepresentation
bin100101001101010101110…
…010000011001101110101
3100001102220212121022101001
4211031111302003031311
5313343110322143403
65234351051203301
7352506321361411
oct45152562031565
910042825538331
102556944724853
118a6437701962
12353677746531
131571711735bc
148ba84891d41
15467a3001c1d
hex25355c83375

2556944724853 has 4 divisors (see below), whose sum is σ = 2557216200960. Its totient is φ = 2556673248748.

The previous prime is 2556944724833. The next prime is 2556944724883. The reversal of 2556944724853 is 3584274496552.

2556944724853 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2556944724853 - 217 = 2556944593781 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2556944724833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135723925 + ... + 135742762.

It is an arithmetic number, because the mean of its divisors is an integer number (639304050240).

Almost surely, 22556944724853 is an apocalyptic number.

It is an amenable number.

2556944724853 is a deficient number, since it is larger than the sum of its proper divisors (271476107).

2556944724853 is an equidigital number, since it uses as much as digits as its factorization.

2556944724853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 271476106.

The product of its digits is 290304000, while the sum is 64.

The spelling of 2556944724853 in words is "two trillion, five hundred fifty-six billion, nine hundred forty-four million, seven hundred twenty-four thousand, eight hundred fifty-three".

Divisors: 1 9419 271466687 2556944724853