Base | Representation |
---|---|
bin | 100101001110001101100… |
… | …110001000001110011011 |
3 | 100001112100010121022011021 |
4 | 211032031212020032123 |
5 | 313402020031424424 |
6 | 5235024021343311 |
7 | 352541451546334 |
oct | 45161546101633 |
9 | 10045303538137 |
10 | 2557881123739 |
11 | 8a6878235237 |
12 | 353899267b37 |
13 | 157290172696 |
14 | 8bb32da528b |
15 | 4680a31d4e4 |
hex | 2538d98839b |
2557881123739 has 2 divisors, whose sum is σ = 2557881123740. Its totient is φ = 2557881123738.
The previous prime is 2557881123697. The next prime is 2557881123793. The reversal of 2557881123739 is 9373211887552.
Together with next prime (2557881123793) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2557881123739 - 213 = 2557881115547 is a prime.
It is not a weakly prime, because it can be changed into another prime (2557881123839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278940561869 + 1278940561870.
It is an arithmetic number, because the mean of its divisors is an integer number (1278940561870).
Almost surely, 22557881123739 is an apocalyptic number.
2557881123739 is a deficient number, since it is larger than the sum of its proper divisors (1).
2557881123739 is an equidigital number, since it uses as much as digits as its factorization.
2557881123739 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25401600, while the sum is 61.
The spelling of 2557881123739 in words is "two trillion, five hundred fifty-seven billion, eight hundred eighty-one million, one hundred twenty-three thousand, seven hundred thirty-nine".
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