Search a number
-
+
2558251147 is a prime number
BaseRepresentation
bin1001100001111011…
…1101000010001011
320121021210121211111
42120132331002023
520214403014042
61101504111151
7120252530104
oct23036750213
96537717744
102558251147
1110a307aa51
125b49054b7
1331a01639a
141a3a953ab
15ee8d5517
hex987bd08b

2558251147 has 2 divisors, whose sum is σ = 2558251148. Its totient is φ = 2558251146.

The previous prime is 2558251141. The next prime is 2558251177. The reversal of 2558251147 is 7411528552.

2558251147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2558251147 - 23 = 2558251139 is a prime.

It is a super-2 number, since 2×25582511472 = 13089297862253631218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2558251141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1279125573 + 1279125574.

It is an arithmetic number, because the mean of its divisors is an integer number (1279125574).

Almost surely, 22558251147 is an apocalyptic number.

2558251147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2558251147 is an equidigital number, since it uses as much as digits as its factorization.

2558251147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 112000, while the sum is 40.

The square root of 2558251147 is about 50579.1572389260. The cubic root of 2558251147 is about 1367.6691763201.

Adding to 2558251147 its reverse (7411528552), we get a palindrome (9969779699).

It can be divided in two parts, 25582 and 51147, that added together give a square (76729 = 2772).

The spelling of 2558251147 in words is "two billion, five hundred fifty-eight million, two hundred fifty-one thousand, one hundred forty-seven".