Base | Representation |
---|---|
bin | 1110111001110010001… |
… | …1111101101100001001 |
3 | 220110212011010120201201 |
4 | 3232130203331230021 |
5 | 13143322103301011 |
6 | 313341325544201 |
7 | 24332440625662 |
oct | 3563443755411 |
9 | 813764116651 |
10 | 256029743881 |
11 | 9964413005a |
12 | 41753a15061 |
13 | 1b1b3370192 |
14 | c56b564369 |
15 | 69d7379cc1 |
hex | 3b9c8fdb09 |
256029743881 has 2 divisors, whose sum is σ = 256029743882. Its totient is φ = 256029743880.
The previous prime is 256029743869. The next prime is 256029743903. The reversal of 256029743881 is 188347920652.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 255925703881 + 104040000 = 505891^2 + 10200^2 .
It is a cyclic number.
It is not a de Polignac number, because 256029743881 - 221 = 256027646729 is a prime.
It is a super-2 number, since 2×2560297438812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (256029743821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128014871940 + 128014871941.
It is an arithmetic number, because the mean of its divisors is an integer number (128014871941).
It is a 1-persistent number, because it is pandigital, but 2⋅256029743881 = 512059487762 is not.
Almost surely, 2256029743881 is an apocalyptic number.
It is an amenable number.
256029743881 is a deficient number, since it is larger than the sum of its proper divisors (1).
256029743881 is an equidigital number, since it uses as much as digits as its factorization.
256029743881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 256029743881 in words is "two hundred fifty-six billion, twenty-nine million, seven hundred forty-three thousand, eight hundred eighty-one".
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