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2561000258689 is a prime number
BaseRepresentation
bin100101010001000111100…
…000101011110010000001
3100001211101111210202220221
4211101013200223302001
5313424412031234224
65240301323303041
7353011655011255
oct45210740536201
910054344722827
102561000258689
118a8128976514
1235440997aa81
1315766943a172
148bd4b340265
154693e0966e4
hex2544782bc81

2561000258689 has 2 divisors, whose sum is σ = 2561000258690. Its totient is φ = 2561000258688.

The previous prime is 2561000258611. The next prime is 2561000258717. The reversal of 2561000258689 is 9868520001652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1855022208064 + 705978050625 = 1361992^2 + 840225^2 .

It is a cyclic number.

It is not a de Polignac number, because 2561000258689 - 229 = 2560463387777 is a prime.

It is a super-3 number, since 3×25610002586893 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2561000258389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280500129344 + 1280500129345.

It is an arithmetic number, because the mean of its divisors is an integer number (1280500129345).

Almost surely, 22561000258689 is an apocalyptic number.

It is an amenable number.

2561000258689 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561000258689 is an equidigital number, since it uses as much as digits as its factorization.

2561000258689 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2073600, while the sum is 52.

The spelling of 2561000258689 in words is "two trillion, five hundred sixty-one billion, two hundred fifty-eight thousand, six hundred eighty-nine".