Base | Representation |
---|---|
bin | 11110100001111… |
… | …00101101101011 |
3 | 122211220021211122 |
4 | 33100330231223 |
5 | 1011030214402 |
6 | 41225045455 |
7 | 6226552544 |
oct | 1720745553 |
9 | 584807748 |
10 | 256101227 |
11 | 121620708 |
12 | 7192688b |
13 | 4109a7b5 |
14 | 260274cb |
15 | 1773bca2 |
hex | f43cb6b |
256101227 has 2 divisors, whose sum is σ = 256101228. Its totient is φ = 256101226.
The previous prime is 256101221. The next prime is 256101257. The reversal of 256101227 is 722101652.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-256101227 is a prime.
It is a super-3 number, since 3×2561012273 (a number of 26 digits) contains 333 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 256101196 and 256101205.
It is not a weakly prime, because it can be changed into another prime (256101221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128050613 + 128050614.
It is an arithmetic number, because the mean of its divisors is an integer number (128050614).
Almost surely, 2256101227 is an apocalyptic number.
256101227 is a deficient number, since it is larger than the sum of its proper divisors (1).
256101227 is an equidigital number, since it uses as much as digits as its factorization.
256101227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 26.
The square root of 256101227 is about 16003.1630311011. The cubic root of 256101227 is about 635.0441013453.
Adding to 256101227 its reverse (722101652), we get a palindrome (978202879).
The spelling of 256101227 in words is "two hundred fifty-six million, one hundred one thousand, two hundred twenty-seven".
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