25610317 has 4 divisors (see below), whose sum is σ = 25625500. Its totient is φ = 25595136.

The previous prime is 25610257. The next prime is 25610323. The reversal of 25610317 is 71301652.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11964681 + 13645636 = 3459^2 + 3694^2 .

It is a cyclic number.

It is not a de Polignac number, because 25610317 - 2¹⁵ = 25577549 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25610291 and 25610300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25611317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4692 + ... + 8557.

It is an arithmetic number, because the mean of its divisors is an integer number (6406375).

Almost surely, 2^25610317 is an apocalyptic number.

It is an amenable number.

25610317 is a deficient number, since it is larger than the sum of its proper divisors (15183).

25610317 is a wasteful number, since it uses less digits than its factorization.

25610317 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15182.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 25610317 is about 5060.6636916515. The cubic root of 25610317 is about 294.7621063998.

Adding to 25610317 its reverse (71301652), we get a palindrome (96911969).

The spelling of 25610317 in words is "twenty-five million, six hundred ten thousand, three hundred seventeen".