256112993894400 has 2592 divisors, whose sum is σ = 1006065407692800. Its totient is φ = 62070246604800.

The previous prime is 256112993894393. The next prime is 256112993894423. The reversal of 256112993894400 is 4498399211652.

256112993894400 is a `hidden beast` number, since 2 + 5 + 6 + 1 + 1 + 29 + 93 + 89 + 440 + 0 = 666.

It is a super-3 number, since 3×256112993894400³ (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 2016637747137 + ... + 2016637747263.

It is an arithmetic number, because the mean of its divisors is an integer number (388142518400).

Almost surely, 2^{256112993894400} is an apocalyptic number.

256112993894400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 256112993894400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (503032703846400).

256112993894400 is an abundant number, since it is smaller than the sum of its proper divisors (749952413798400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

256112993894400 is a wasteful number, since it uses less digits than its factorization.

256112993894400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 316 (or 276 counting only the distinct ones).

The product of its (nonzero) digits is 33592320, while the sum is 63.

The spelling of 256112993894400 in words is "two hundred fifty-six trillion, one hundred twelve billion, nine hundred ninety-three million, eight hundred ninety-four thousand, four hundred".