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25613351131393 is a prime number
BaseRepresentation
bin1011101001011100100101…
…01100100001100100000001
310100200121112110221102202001
411310232102230201210001
511324122120342201033
6130250335554024001
75252334501255304
oct564562254414401
9110617473842661
1025613351131393
118185619a7a783
122a58057578001
13113a43706833c
1464799b0d6b3b
152e63de5d5e7d
hex174b92b21901

25613351131393 has 2 divisors, whose sum is σ = 25613351131394. Its totient is φ = 25613351131392.

The previous prime is 25613351131309. The next prime is 25613351131427. The reversal of 25613351131393 is 39313115331652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15492859593409 + 10120491537984 = 3936097^2 + 3181272^2 .

It is a cyclic number.

It is not a de Polignac number, because 25613351131393 - 225 = 25613317576961 is a prime.

It is not a weakly prime, because it can be changed into another prime (25613351131793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12806675565696 + 12806675565697.

It is an arithmetic number, because the mean of its divisors is an integer number (12806675565697).

Almost surely, 225613351131393 is an apocalyptic number.

It is an amenable number.

25613351131393 is a deficient number, since it is larger than the sum of its proper divisors (1).

25613351131393 is an equidigital number, since it uses as much as digits as its factorization.

25613351131393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 656100, while the sum is 46.

The spelling of 25613351131393 in words is "twenty-five trillion, six hundred thirteen billion, three hundred fifty-one million, one hundred thirty-one thousand, three hundred ninety-three".