Base | Representation |
---|---|
bin | 100101010001011111011… |
… | …010010010000100100001 |
3 | 100001212102110022102020011 |
4 | 211101133122102010201 |
5 | 313431222203434242 |
6 | 5240405205444521 |
7 | 353024624153515 |
oct | 45213732220441 |
9 | 10055373272204 |
10 | 2561401233697 |
11 | 8a8314247a19 |
12 | 354500110741 |
13 | 157701530497 |
14 | 8bd886ba145 |
15 | 4696439dd17 |
hex | 2545f692121 |
2561401233697 has 2 divisors, whose sum is σ = 2561401233698. Its totient is φ = 2561401233696.
The previous prime is 2561401233691. The next prime is 2561401233739. The reversal of 2561401233697 is 7963321041652.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1903492068241 + 657909165456 = 1379671^2 + 811116^2 .
It is a cyclic number.
It is not a de Polignac number, because 2561401233697 - 23 = 2561401233689 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2561401233697.
It is not a weakly prime, because it can be changed into another prime (2561401233691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280700616848 + 1280700616849.
It is an arithmetic number, because the mean of its divisors is an integer number (1280700616849).
Almost surely, 22561401233697 is an apocalyptic number.
It is an amenable number.
2561401233697 is a deficient number, since it is larger than the sum of its proper divisors (1).
2561401233697 is an equidigital number, since it uses as much as digits as its factorization.
2561401233697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 2561401233697 in words is "two trillion, five hundred sixty-one billion, four hundred one million, two hundred thirty-three thousand, six hundred ninety-seven".
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