Base | Representation |
---|---|
bin | 100101010001100110110… |
… | …010100100010100101011 |
3 | 100001212202002021110010121 |
4 | 211101212302210110223 |
5 | 313432000402243202 |
6 | 5240425351224111 |
7 | 353030656411213 |
oct | 45214662442453 |
9 | 10055662243117 |
10 | 2561525040427 |
11 | 8a8378119831 |
12 | 354535678037 |
13 | 15772108acc2 |
14 | 8bd9ad07243 |
15 | 469701a7537 |
hex | 25466ca452b |
2561525040427 has 2 divisors, whose sum is σ = 2561525040428. Its totient is φ = 2561525040426.
The previous prime is 2561525040383. The next prime is 2561525040443. The reversal of 2561525040427 is 7240405251652.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2561525040427 - 211 = 2561525038379 is a prime.
It is a super-2 number, since 2×25615250404272 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2561525020427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280762520213 + 1280762520214.
It is an arithmetic number, because the mean of its divisors is an integer number (1280762520214).
Almost surely, 22561525040427 is an apocalyptic number.
2561525040427 is a deficient number, since it is larger than the sum of its proper divisors (1).
2561525040427 is an equidigital number, since it uses as much as digits as its factorization.
2561525040427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672000, while the sum is 43.
The spelling of 2561525040427 in words is "two trillion, five hundred sixty-one billion, five hundred twenty-five million, forty thousand, four hundred twenty-seven".
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