Base | Representation |
---|---|
bin | 1110111010010000001… |
… | …1011000011010001110 |
3 | 220111011220121121100222 |
4 | 3232210003120122032 |
5 | 13144101241422202 |
6 | 313402015351342 |
7 | 24335525101355 |
oct | 3564403303216 |
9 | 814156547328 |
10 | 256155420302 |
11 | 996a9069671 |
12 | 41789b22552 |
13 | 1b203403a22 |
14 | c58011a99c |
15 | 69e34024a2 |
hex | 3ba40d868e |
256155420302 has 4 divisors (see below), whose sum is σ = 384233130456. Its totient is φ = 128077710150.
The previous prime is 256155420223. The next prime is 256155420307. The reversal of 256155420302 is 203024551652.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (256155420307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64038855074 + ... + 64038855077.
It is an arithmetic number, because the mean of its divisors is an integer number (96058282614).
Almost surely, 2256155420302 is an apocalyptic number.
256155420302 is a deficient number, since it is larger than the sum of its proper divisors (128077710154).
256155420302 is a wasteful number, since it uses less digits than its factorization.
256155420302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128077710153.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 256155420302 its reverse (203024551652), we get a palindrome (459179971954).
The spelling of 256155420302 in words is "two hundred fifty-six billion, one hundred fifty-five million, four hundred twenty thousand, three hundred two".
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