Base | Representation |
---|---|
bin | 100101010001101100000… |
… | …010010011100100001111 |
3 | 100001212222012212220112222 |
4 | 211101230002103210033 |
5 | 313432140420132200 |
6 | 5240442213445555 |
7 | 353033105453222 |
oct | 45215402234417 |
9 | 10055865786488 |
10 | 2561613052175 |
11 | 8a8412872311 |
12 | 35455b0408bb |
13 | 157736394c68 |
14 | 8bda88975b9 |
15 | 46977c8ed85 |
hex | 2546c09390f |
2561613052175 has 6 divisors (see below), whose sum is σ = 3176400184728. Its totient is φ = 2049290441720.
The previous prime is 2561613052133. The next prime is 2561613052217. The reversal of 2561613052175 is 5712503161652.
It is an interprime number because it is at equal distance from previous prime (2561613052133) and next prime (2561613052217).
It is not a de Polignac number, because 2561613052175 - 232 = 2557318084879 is a prime.
It is a super-2 number, since 2×25616130521752 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 51232261019 + ... + 51232261068.
It is an arithmetic number, because the mean of its divisors is an integer number (529400030788).
Almost surely, 22561613052175 is an apocalyptic number.
2561613052175 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2561613052175 is a deficient number, since it is larger than the sum of its proper divisors (614787132553).
2561613052175 is a wasteful number, since it uses less digits than its factorization.
2561613052175 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102464522097 (or 102464522092 counting only the distinct ones).
The product of its (nonzero) digits is 378000, while the sum is 44.
The spelling of 2561613052175 in words is "two trillion, five hundred sixty-one billion, six hundred thirteen million, fifty-two thousand, one hundred seventy-five".
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