Base | Representation |
---|---|
bin | 1110111010010010001… |
… | …0010000011010011011 |
3 | 220111012110211210211222 |
4 | 3232210202100122123 |
5 | 13144110324422021 |
6 | 313402505042255 |
7 | 24335653641236 |
oct | 3564442203233 |
9 | 814173753758 |
10 | 256163514011 |
11 | 99702697589 |
12 | 4179078638b |
13 | 1b204ca89c2 |
14 | c58122641d |
15 | 69e3ea06ab |
hex | 3ba489069b |
256163514011 has 2 divisors, whose sum is σ = 256163514012. Its totient is φ = 256163514010.
The previous prime is 256163513987. The next prime is 256163514037. The reversal of 256163514011 is 110415361652.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 256163514011 - 218 = 256163251867 is a prime.
It is not a weakly prime, because it can be changed into another prime (256163514071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128081757005 + 128081757006.
It is an arithmetic number, because the mean of its divisors is an integer number (128081757006).
Almost surely, 2256163514011 is an apocalyptic number.
256163514011 is a deficient number, since it is larger than the sum of its proper divisors (1).
256163514011 is an equidigital number, since it uses as much as digits as its factorization.
256163514011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
Adding to 256163514011 its reverse (110415361652), we get a palindrome (366578875663).
The spelling of 256163514011 in words is "two hundred fifty-six billion, one hundred sixty-three million, five hundred fourteen thousand, eleven".
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