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2563147 is a prime number
BaseRepresentation
bin1001110001110001001011
311211012222101
421301301023
51124010042
6130534231
730533506
oct11616113
94735871
102563147
1114a0804
12a37377
136b9872
144aa13d
153596b7
hex271c4b

2563147 has 2 divisors, whose sum is σ = 2563148. Its totient is φ = 2563146.

The previous prime is 2563139. The next prime is 2563151. The reversal of 2563147 is 7413652.

2563147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2563147 - 23 = 2563139 is a prime.

It is a Chen prime.

It is equal to p187354 and since 2563147 and 187354 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (2563117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1281573 + 1281574.

It is an arithmetic number, because the mean of its divisors is an integer number (1281574).

22563147 is an apocalyptic number.

2563147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2563147 is an equidigital number, since it uses as much as digits as its factorization.

2563147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 28.

The square root of 2563147 is about 1600.9831354515. The cubic root of 2563147 is about 136.8541079293.

Adding to 2563147 its reverse (7413652), we get a palindrome (9976799).

It can be divided in two parts, 256 and 3147, that added together give a triangular number (3403 = T82).

The spelling of 2563147 in words is "two million, five hundred sixty-three thousand, one hundred forty-seven".