Base | Representation |
---|---|
bin | 1011101010001111000011… |
… | …01001101110010101100011 |
3 | 10100210012110201222002212221 |
4 | 11311013201221232111203 |
5 | 11330043113033213443 |
6 | 130311020314331511 |
7 | 5254314100411363 |
oct | 565074151562543 |
9 | 110705421862787 |
10 | 25640445601123 |
11 | 8196063107921 |
12 | 2a61359429b97 |
13 | 113cb644a4452 |
14 | 64900b6ca9a3 |
15 | 2e6e780cbeed |
hex | 1751e1a6e563 |
25640445601123 has 2 divisors, whose sum is σ = 25640445601124. Its totient is φ = 25640445601122.
The previous prime is 25640445601079. The next prime is 25640445601181. The reversal of 25640445601123 is 32110654404652.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25640445601123 is a prime.
It is a super-3 number, since 3×256404456011233 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 25640445601123.
It is not a weakly prime, because it can be changed into another prime (25640445601223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12820222800561 + 12820222800562.
It is an arithmetic number, because the mean of its divisors is an integer number (12820222800562).
Almost surely, 225640445601123 is an apocalyptic number.
25640445601123 is a deficient number, since it is larger than the sum of its proper divisors (1).
25640445601123 is an equidigital number, since it uses as much as digits as its factorization.
25640445601123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 43.
The spelling of 25640445601123 in words is "twenty-five trillion, six hundred forty billion, four hundred forty-five million, six hundred one thousand, one hundred twenty-three".
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