Base | Representation |
---|---|
bin | 1001100011011000… |
… | …1011101000111001 |
3 | 20121201020222112222 |
4 | 2120312023220321 |
5 | 20222432342111 |
6 | 1102242413425 |
7 | 120355350506 |
oct | 23066135071 |
9 | 6551228488 |
10 | 2564340281 |
11 | 10a6559898 |
12 | 5b6961275 |
13 | 31b368b19 |
14 | 1a47dc4ad |
15 | 1001d97db |
hex | 98d8ba39 |
2564340281 has 2 divisors, whose sum is σ = 2564340282. Its totient is φ = 2564340280.
The previous prime is 2564340211. The next prime is 2564340307. The reversal of 2564340281 is 1820434652.
2564340281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2198765881 + 365574400 = 46891^2 + 19120^2 .
It is a cyclic number.
It is not a de Polignac number, because 2564340281 - 210 = 2564339257 is a prime.
It is a super-2 number, since 2×25643402812 = 13151682153518317922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2564340211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1282170140 + 1282170141.
It is an arithmetic number, because the mean of its divisors is an integer number (1282170141).
Almost surely, 22564340281 is an apocalyptic number.
It is an amenable number.
2564340281 is a deficient number, since it is larger than the sum of its proper divisors (1).
2564340281 is an equidigital number, since it uses as much as digits as its factorization.
2564340281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 35.
The square root of 2564340281 is about 50639.3155660698. The cubic root of 2564340281 is about 1368.7534225195.
The spelling of 2564340281 in words is "two billion, five hundred sixty-four million, three hundred forty thousand, two hundred eighty-one".
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