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256517300253113 is a prime number
BaseRepresentation
bin111010010100110100010110…
…100011110111000110111001
31020122020210222201000111121022
4322110310112203313012321
5232110234412331044423
62305322230525352225
7105013522555123304
oct7224642643670671
91218223881014538
10256517300253113
1174809415667529
122492a930a08675
13b01962943bb73
14474b709b5bb3b
151e9c90c500dc8
hexe94d168f71b9

256517300253113 has 2 divisors, whose sum is σ = 256517300253114. Its totient is φ = 256517300253112.

The previous prime is 256517300253101. The next prime is 256517300253119. The reversal of 256517300253113 is 311352003715652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 206529176281129 + 49988123971984 = 14371123^2 + 7070228^2 .

It is a cyclic number.

It is not a de Polignac number, because 256517300253113 - 210 = 256517300252089 is a prime.

It is a super-2 number, since 2×2565173002531132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (256517300253119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128258650126556 + 128258650126557.

It is an arithmetic number, because the mean of its divisors is an integer number (128258650126557).

Almost surely, 2256517300253113 is an apocalyptic number.

It is an amenable number.

256517300253113 is a deficient number, since it is larger than the sum of its proper divisors (1).

256517300253113 is an equidigital number, since it uses as much as digits as its factorization.

256517300253113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567000, while the sum is 44.

Adding to 256517300253113 its reverse (311352003715652), we get a palindrome (567869303968765).

The spelling of 256517300253113 in words is "two hundred fifty-six trillion, five hundred seventeen billion, three hundred million, two hundred fifty-three thousand, one hundred thirteen".