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256541153137 is a prime number
BaseRepresentation
bin1110111011101100001…
…0110101011101110001
3220112011210102212100021
43232323002311131301
513200344013400022
6313504155123441
724351220552033
oct3567302653561
9815153385307
10256541153137
119988687a435
1241877143581
131b2652bb3c9
14c5b9449c53
156a171e87c7
hex3bbb0b5771

256541153137 has 2 divisors, whose sum is σ = 256541153138. Its totient is φ = 256541153136.

The previous prime is 256541153059. The next prime is 256541153237. The reversal of 256541153137 is 731351145652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 207397357281 + 49143795856 = 455409^2 + 221684^2 .

It is a cyclic number.

It is not a de Polignac number, because 256541153137 - 231 = 254393669489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 256541153093 and 256541153102.

It is not a weakly prime, because it can be changed into another prime (256541153237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128270576568 + 128270576569.

It is an arithmetic number, because the mean of its divisors is an integer number (128270576569).

Almost surely, 2256541153137 is an apocalyptic number.

It is an amenable number.

256541153137 is a deficient number, since it is larger than the sum of its proper divisors (1).

256541153137 is an equidigital number, since it uses as much as digits as its factorization.

256541153137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 378000, while the sum is 43.

Adding to 256541153137 its reverse (731351145652), we get a palindrome (987892298789).

The spelling of 256541153137 in words is "two hundred fifty-six billion, five hundred forty-one million, one hundred fifty-three thousand, one hundred thirty-seven".