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25655234141 = 64739652603
BaseRepresentation
bin10111111001001010…
…111100111001011101
32110012221211221002002
4113321022330321131
5410020214443031
615441424412045
71565521614665
oct277112747135
973187757062
1025655234141
11a975790149
124b7ba77025
13255b200a24
1413553cb1a5
15a024a0ccb
hex5f92bce5d

25655234141 has 4 divisors (see below), whose sum is σ = 25694887392. Its totient is φ = 25615580892.

The previous prime is 25655234131. The next prime is 25655234161. The reversal of 25655234141 is 14143255652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25655234141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25655234095 and 25655234104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25655234131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19825655 + ... + 19826948.

It is an arithmetic number, because the mean of its divisors is an integer number (6423721848).

Almost surely, 225655234141 is an apocalyptic number.

It is an amenable number.

25655234141 is a deficient number, since it is larger than the sum of its proper divisors (39653251).

25655234141 is an equidigital number, since it uses as much as digits as its factorization.

25655234141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39653250.

The product of its digits is 144000, while the sum is 38.

Adding to 25655234141 its reverse (14143255652), we get a palindrome (39798489793).

The spelling of 25655234141 in words is "twenty-five billion, six hundred fifty-five million, two hundred thirty-four thousand, one hundred forty-one".

Divisors: 1 647 39652603 25655234141