Base | Representation |
---|---|
bin | 1110111100010010001… |
… | …0111010001001000011 |
3 | 220112120220101100202012 |
4 | 3233010202322021003 |
5 | 13201210320241333 |
6 | 313532051443135 |
7 | 24355164502664 |
oct | 3570442721103 |
9 | 815526340665 |
10 | 256700555843 |
11 | 99958854006 |
12 | 419005b64ab |
13 | 1b28c330034 |
14 | c5d26a136b |
15 | 6a261d3e48 |
hex | 3bc48ba243 |
256700555843 has 2 divisors, whose sum is σ = 256700555844. Its totient is φ = 256700555842.
The previous prime is 256700555809. The next prime is 256700555869. The reversal of 256700555843 is 348555007652.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 256700555843 - 26 = 256700555779 is a prime.
It is a super-2 number, since 2×2567005558432 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 256700555791 and 256700555800.
It is not a weakly prime, because it can be changed into another prime (256700555893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128350277921 + 128350277922.
It is an arithmetic number, because the mean of its divisors is an integer number (128350277922).
Almost surely, 2256700555843 is an apocalyptic number.
256700555843 is a deficient number, since it is larger than the sum of its proper divisors (1).
256700555843 is an equidigital number, since it uses as much as digits as its factorization.
256700555843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040000, while the sum is 50.
The spelling of 256700555843 in words is "two hundred fifty-six billion, seven hundred million, five hundred fifty-five thousand, eight hundred forty-three".
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