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256919713 is a prime number
BaseRepresentation
bin11110101000001…
…00100010100001
3122220102212120221
433110010202201
51011232412323
641254403041
76236532031
oct1724044241
9586385527
10256919713
1112202a646
1272060481
13412c61cb
142619b8c1
151784e55d
hexf5048a1

256919713 has 2 divisors, whose sum is σ = 256919714. Its totient is φ = 256919712.

The previous prime is 256919693. The next prime is 256919731. The reversal of 256919713 is 317919652.

Together with next prime (256919731) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 256736529 + 183184 = 16023^2 + 428^2 .

It is a cyclic number.

It is not a de Polignac number, because 256919713 - 25 = 256919681 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 256919713.

It is not a weakly prime, because it can be changed into another prime (256919743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128459856 + 128459857.

It is an arithmetic number, because the mean of its divisors is an integer number (128459857).

Almost surely, 2256919713 is an apocalyptic number.

It is an amenable number.

256919713 is a deficient number, since it is larger than the sum of its proper divisors (1).

256919713 is an equidigital number, since it uses as much as digits as its factorization.

256919713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 102060, while the sum is 43.

The square root of 256919713 is about 16028.7152635512. The cubic root of 256919713 is about 635.7199043852.

The spelling of 256919713 in words is "two hundred fifty-six million, nine hundred nineteen thousand, seven hundred thirteen".