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256949314860067 is a prime number
BaseRepresentation
bin111010011011000110101100…
…101000110011010000100011
31020200210010002112201102011121
4322123012230220303100203
5232134324144101010232
62310252515145553111
7105056655361522654
oct7233065450632043
91220703075642147
10256949314860067
1174965657646985
122499a5b97a5797
13b04b2a76320cb
1447645adb4752b
151ea8c9481dd97
hexe9b1aca33423

256949314860067 has 2 divisors, whose sum is σ = 256949314860068. Its totient is φ = 256949314860066.

The previous prime is 256949314859917. The next prime is 256949314860103. The reversal of 256949314860067 is 760068413949652.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 256949314860067 - 215 = 256949314827299 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 256949314859978 and 256949314860005.

It is not a weakly prime, because it can be changed into another prime (256949314860467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128474657430033 + 128474657430034.

It is an arithmetic number, because the mean of its divisors is an integer number (128474657430034).

It is a 2-persistent number, because it is pandigital, and so is 2⋅256949314860067 = 513898629720134, but 3⋅256949314860067 = 770847944580201 is not.

Almost surely, 2256949314860067 is an apocalyptic number.

256949314860067 is a deficient number, since it is larger than the sum of its proper divisors (1).

256949314860067 is an equidigital number, since it uses as much as digits as its factorization.

256949314860067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 470292480, while the sum is 70.

The spelling of 256949314860067 in words is "two hundred fifty-six trillion, nine hundred forty-nine billion, three hundred fourteen million, eight hundred sixty thousand, sixty-seven".