Base | Representation |
---|---|
bin | 11110101001100… |
… | …11111110110011 |
3 | 122220210202011001 |
4 | 33110303332303 |
5 | 1011310122120 |
6 | 41302502431 |
7 | 6241301413 |
oct | 1724637663 |
9 | 586722131 |
10 | 257114035 |
11 | 122152642 |
12 | 72134a17 |
13 | 413637a9 |
14 | 2620c643 |
15 | 1788be0a |
hex | f533fb3 |
257114035 has 32 divisors (see below), whose sum is σ = 335301120. Its totient is φ = 188554752.
The previous prime is 257114027. The next prime is 257114063. The reversal of 257114035 is 530411752.
257114035 = T2417 + T2418 + ... + T2501.
It is a happy number.
It is not a de Polignac number, because 257114035 - 23 = 257114027 is a prime.
It is a super-2 number, since 2×2571140352 = 132215253987962450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 257113994 and 257114012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 837352 + ... + 837658.
It is an arithmetic number, because the mean of its divisors is an integer number (10478160).
Almost surely, 2257114035 is an apocalyptic number.
257114035 is a deficient number, since it is larger than the sum of its proper divisors (78187085).
257114035 is a wasteful number, since it uses less digits than its factorization.
257114035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 555.
The product of its (nonzero) digits is 4200, while the sum is 28.
The square root of 257114035 is about 16034.7758013637. The cubic root of 257114035 is about 635.8801402162.
Adding to 257114035 its reverse (530411752), we get a palindrome (787525787).
The spelling of 257114035 in words is "two hundred fifty-seven million, one hundred fourteen thousand, thirty-five".
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