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257133594953 is a prime number
BaseRepresentation
bin1110111101111001011…
…0110100100101001001
3220120201002020000201202
43233132112310211021
513203102200014303
6314043041153545
724402003331454
oct3573626644511
9816632200652
10257133594953
119a060235774
1241a0162b8b5
131b32ac6b9b1
14c633dc649b
156a4e221c88
hex3bde5b4949

257133594953 has 2 divisors, whose sum is σ = 257133594954. Its totient is φ = 257133594952.

The previous prime is 257133594941. The next prime is 257133594967. The reversal of 257133594953 is 359495331752.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 253621017664 + 3512577289 = 503608^2 + 59267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-257133594953 is a prime.

It is a super-3 number, since 3×2571335949533 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (257133594973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128566797476 + 128566797477.

It is an arithmetic number, because the mean of its divisors is an integer number (128566797477).

Almost surely, 2257133594953 is an apocalyptic number.

It is an amenable number.

257133594953 is a deficient number, since it is larger than the sum of its proper divisors (1).

257133594953 is an equidigital number, since it uses as much as digits as its factorization.

257133594953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15309000, while the sum is 56.

The spelling of 257133594953 in words is "two hundred fifty-seven billion, one hundred thirty-three million, five hundred ninety-four thousand, nine hundred fifty-three".