Base | Representation |
---|---|
bin | 11000000001011111… |
… | …111011010101011101 |
3 | 2110120200202020212210 |
4 | 120001133323111131 |
5 | 410312001403433 |
6 | 15503335151033 |
7 | 1602136314204 |
oct | 300137732535 |
9 | 73520666783 |
10 | 25794950493 |
11 | aa37639104 |
12 | 4bba815479 |
13 | 258113bc20 |
14 | 1369b9a23b |
15 | a0e89d463 |
hex | 6017fb55d |
25794950493 has 32 divisors (see below), whose sum is σ = 39344078592. Its totient is φ = 14891904000.
The previous prime is 25794950417. The next prime is 25794950507. The reversal of 25794950493 is 39405949752.
It is not a de Polignac number, because 25794950493 - 216 = 25794884957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25794950413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 143643 + ... + 268743.
It is an arithmetic number, because the mean of its divisors is an integer number (1229502456).
Almost surely, 225794950493 is an apocalyptic number.
It is an amenable number.
25794950493 is a deficient number, since it is larger than the sum of its proper divisors (13549128099).
25794950493 is a wasteful number, since it uses less digits than its factorization.
25794950493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125445.
The product of its (nonzero) digits is 12247200, while the sum is 57.
The spelling of 25794950493 in words is "twenty-five billion, seven hundred ninety-four million, nine hundred fifty thousand, four hundred ninety-three".
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