Base | Representation |
---|---|
bin | 100101100100000111111… |
… | …010011000000100010011 |
3 | 100010210001202201221021112 |
4 | 211210013322120010103 |
5 | 314243210432311324 |
6 | 5253514342043535 |
7 | 354333461500013 |
oct | 45440772300423 |
9 | 10123052657245 |
10 | 2581408088339 |
11 | 905850628a33 |
12 | 3583644195ab |
13 | 15956c468102 |
14 | 8cd25867c43 |
15 | 47235a20c0e |
hex | 25907e98113 |
2581408088339 has 2 divisors, whose sum is σ = 2581408088340. Its totient is φ = 2581408088338.
The previous prime is 2581408088293. The next prime is 2581408088383. The reversal of 2581408088339 is 9338808041852.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2581408088339 - 220 = 2581407039763 is a prime.
It is not a weakly prime, because it can be changed into another prime (2581408088239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1290704044169 + 1290704044170.
It is an arithmetic number, because the mean of its divisors is an integer number (1290704044170).
Almost surely, 22581408088339 is an apocalyptic number.
2581408088339 is a deficient number, since it is larger than the sum of its proper divisors (1).
2581408088339 is an equidigital number, since it uses as much as digits as its factorization.
2581408088339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13271040, while the sum is 59.
The spelling of 2581408088339 in words is "two trillion, five hundred eighty-one billion, four hundred eight million, eighty-eight thousand, three hundred thirty-nine".
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