Base | Representation |
---|---|
bin | 1111000001101111011… |
… | …0101001101011001111 |
3 | 220200100222122120022020 |
4 | 3300123312221223033 |
5 | 13212210312132241 |
6 | 314333255221223 |
7 | 24436402155120 |
oct | 3603366515317 |
9 | 820328576266 |
10 | 258165349071 |
11 | 9a53a677923 |
12 | 4204b077813 |
13 | 1b4639463a6 |
14 | c6d103c047 |
15 | 6aaeac6b66 |
hex | 3c1bda9acf |
258165349071 has 32 divisors (see below), whose sum is σ = 403798080000. Its totient is φ = 143636267520.
The previous prime is 258165349037. The next prime is 258165349081. The reversal of 258165349071 is 170943561852.
It is not a de Polignac number, because 258165349071 - 26 = 258165349007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (258165349081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 129195 + ... + 730083.
It is an arithmetic number, because the mean of its divisors is an integer number (12618690000).
It is a 1-persistent number, because it is pandigital, but 2⋅258165349071 = 516330698142 is not.
Almost surely, 2258165349071 is an apocalyptic number.
258165349071 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
258165349071 is a deficient number, since it is larger than the sum of its proper divisors (145632730929).
258165349071 is a wasteful number, since it uses less digits than its factorization.
258165349071 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 601439.
The product of its (nonzero) digits is 1814400, while the sum is 51.
The spelling of 258165349071 in words is "two hundred fifty-eight billion, one hundred sixty-five million, three hundred forty-nine thousand, seventy-one".
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