Base | Representation |
---|---|
bin | 100101100101110000001… |
… | …010011101010001101011 |
3 | 100010221120122212200110212 |
4 | 211211300022131101223 |
5 | 314310301211300233 |
6 | 5254404102131335 |
7 | 354425020234544 |
oct | 45456012352153 |
9 | 10127518780425 |
10 | 2583157134443 |
11 | 906568950186 |
12 | 358772120b4b |
13 | 15978a927832 |
14 | 8d04dc794cb |
15 | 472d9361a48 |
hex | 2597029d46b |
2583157134443 has 2 divisors, whose sum is σ = 2583157134444. Its totient is φ = 2583157134442.
The previous prime is 2583157134353. The next prime is 2583157134497. The reversal of 2583157134443 is 3444317513852.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2583157134443 - 236 = 2514437657707 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2583157134391 and 2583157134400.
It is not a weakly prime, because it can be changed into another prime (2583157134343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1291578567221 + 1291578567222.
It is an arithmetic number, because the mean of its divisors is an integer number (1291578567222).
Almost surely, 22583157134443 is an apocalyptic number.
2583157134443 is a deficient number, since it is larger than the sum of its proper divisors (1).
2583157134443 is an equidigital number, since it uses as much as digits as its factorization.
2583157134443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4838400, while the sum is 50.
The spelling of 2583157134443 in words is "two trillion, five hundred eighty-three billion, one hundred fifty-seven million, one hundred thirty-four thousand, four hundred forty-three".
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