Base | Representation |
---|---|
bin | 111010111000000110100011… |
… | …000110111100000101111001 |
3 | 1020221211121121120122111220011 |
4 | 322320012203012330011321 |
5 | 232420001224033020003 |
6 | 2314420153252501521 |
7 | 105353641433253313 |
oct | 7270064306740571 |
9 | 1227747546574804 |
10 | 258942019813753 |
11 | 7556376a642471 |
12 | 2506084661a8a1 |
13 | b164187708413 |
14 | 47d2c097d67b3 |
15 | 1ee0a2215146d |
hex | eb81a31bc179 |
258942019813753 has 2 divisors, whose sum is σ = 258942019813754. Its totient is φ = 258942019813752.
The previous prime is 258942019813733. The next prime is 258942019813777. The reversal of 258942019813753 is 357318910249852.
258942019813753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 252961295229049 + 5980724584704 = 15904757^2 + 2445552^2 .
It is a cyclic number.
It is not a de Polignac number, because 258942019813753 - 25 = 258942019813721 is a prime.
It is not a weakly prime, because it can be changed into another prime (258942019813733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129471009906876 + 129471009906877.
It is an arithmetic number, because the mean of its divisors is an integer number (129471009906877).
Almost surely, 2258942019813753 is an apocalyptic number.
It is an amenable number.
258942019813753 is a deficient number, since it is larger than the sum of its proper divisors (1).
258942019813753 is an equidigital number, since it uses as much as digits as its factorization.
258942019813753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 130636800, while the sum is 67.
The spelling of 258942019813753 in words is "two hundred fifty-eight trillion, nine hundred forty-two billion, nineteen million, eight hundred thirteen thousand, seven hundred fifty-three".
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