Base | Representation |
---|---|
bin | 1011110010000100100101… |
… | …01101011100001110101001 |
3 | 10101201221110211100211200010 |
4 | 11321002102231130032221 |
5 | 11344001033223140423 |
6 | 131034430451002133 |
7 | 5312625423126300 |
oct | 571022255341651 |
9 | 111657424324603 |
10 | 25909704115113 |
11 | 828a275565735 |
12 | 2aa5583599349 |
13 | 115c375434840 |
14 | 658071b2b437 |
15 | 2ede869e7693 |
hex | 179092b5c3a9 |
25909704115113 has 48 divisors (see below), whose sum is σ = 44284206918336. Its totient is φ = 13348827838080.
The previous prime is 25909704115093. The next prime is 25909704115151. The reversal of 25909704115113 is 31151140790952.
It is not a de Polignac number, because 25909704115113 - 213 = 25909704106921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (25909704117113) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 157571218 + ... + 157735563.
It is an arithmetic number, because the mean of its divisors is an integer number (922587644132).
Almost surely, 225909704115113 is an apocalyptic number.
It is an amenable number.
25909704115113 is a deficient number, since it is larger than the sum of its proper divisors (18374502803223).
25909704115113 is a wasteful number, since it uses less digits than its factorization.
25909704115113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 315306854 (or 315306847 counting only the distinct ones).
The product of its (nonzero) digits is 340200, while the sum is 48.
The spelling of 25909704115113 in words is "twenty-five trillion, nine hundred nine billion, seven hundred four million, one hundred fifteen thousand, one hundred thirteen".
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