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2591138014051 is a prime number
BaseRepresentation
bin100101101101001011110…
…111000110001101100011
3100011201011212022101010111
4211231023313012031203
5314423122312422201
65302204040112151
7355126546501246
oct45551367061543
910151155271114
102591138014051
11909993949154
1235a21aa65657
1315a4602049c2
148d5a9ba725d
1547604d31b51
hex25b4bdc6363

2591138014051 has 2 divisors, whose sum is σ = 2591138014052. Its totient is φ = 2591138014050.

The previous prime is 2591138014033. The next prime is 2591138014061. The reversal of 2591138014051 is 1504108311952.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2591138014051 - 25 = 2591138014019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2591138013995 and 2591138014013.

It is not a weakly prime, because it can be changed into another prime (2591138014001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1295569007025 + 1295569007026.

It is an arithmetic number, because the mean of its divisors is an integer number (1295569007026).

Almost surely, 22591138014051 is an apocalyptic number.

2591138014051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2591138014051 is an equidigital number, since it uses as much as digits as its factorization.

2591138014051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 40.

The spelling of 2591138014051 in words is "two trillion, five hundred ninety-one billion, one hundred thirty-eight million, fourteen thousand, fifty-one".