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2598130025857 is a prime number
BaseRepresentation
bin100101110011101100100…
…111100000010110000001
3100012101020011000101011201
4211303230213200112001
5320031432241311412
65305321531141201
7355465040560312
oct45635447402601
910171204011151
102598130025857
11911951737103
1235b6505a4801
1315b0059719b2
148da70644609
15478b3abde57
hex25cec9e0581

2598130025857 has 2 divisors, whose sum is σ = 2598130025858. Its totient is φ = 2598130025856.

The previous prime is 2598130025809. The next prime is 2598130025917. The reversal of 2598130025857 is 7585200318952.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2536498984321 + 61631041536 = 1592639^2 + 248256^2 .

It is a cyclic number.

It is not a de Polignac number, because 2598130025857 - 215 = 2598129993089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2598130025798 and 2598130025807.

It is not a weakly prime, because it can be changed into another prime (2598130025807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1299065012928 + 1299065012929.

It is an arithmetic number, because the mean of its divisors is an integer number (1299065012929).

Almost surely, 22598130025857 is an apocalyptic number.

It is an amenable number.

2598130025857 is a deficient number, since it is larger than the sum of its proper divisors (1).

2598130025857 is an equidigital number, since it uses as much as digits as its factorization.

2598130025857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048000, while the sum is 55.

The spelling of 2598130025857 in words is "two trillion, five hundred ninety-eight billion, one hundred thirty million, twenty-five thousand, eight hundred fifty-seven".