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25990772057 = 67387921971
BaseRepresentation
bin11000001101001010…
…111011010101011001
32111002100020000120022
4120031022323111121
5411212114201212
615535012240225
71610034626435
oct301512732531
974070200508
1025990772057
1110028127808
125054310075
1325b2892383
141387bb19c5
15a21b7e772
hex60d2bb559

25990772057 has 4 divisors (see below), whose sum is σ = 26378694096. Its totient is φ = 25602850020.

The previous prime is 25990772039. The next prime is 25990772117. The reversal of 25990772057 is 75027709952.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25990772057 - 210 = 25990771033 is a prime.

It is a super-2 number, since 2×259907720572 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25990772257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193960919 + ... + 193961052.

It is an arithmetic number, because the mean of its divisors is an integer number (6594673524).

Almost surely, 225990772057 is an apocalyptic number.

It is an amenable number.

25990772057 is a deficient number, since it is larger than the sum of its proper divisors (387922039).

25990772057 is an equidigital number, since it uses as much as digits as its factorization.

25990772057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 387922038.

The product of its (nonzero) digits is 2778300, while the sum is 53.

The spelling of 25990772057 in words is "twenty-five billion, nine hundred ninety million, seven hundred seventy-two thousand, fifty-seven".

Divisors: 1 67 387921971 25990772057