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26023433 is a prime number
BaseRepresentation
bin110001101000…
…1011000001001
31210222010102212
41203101120021
523130222213
62325434505
7434124032
oct143213011
953863385
1026023433
1113764877
12886ba35
135511ca7
143655a89
1524409a8
hex18d1609

26023433 has 2 divisors, whose sum is σ = 26023434. Its totient is φ = 26023432.

The previous prime is 26023427. The next prime is 26023453. The reversal of 26023433 is 33432062.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22534009 + 3489424 = 4747^2 + 1868^2 .

It is a cyclic number.

It is not a de Polignac number, because 26023433 - 212 = 26019337 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 26023399 and 26023408.

It is not a weakly prime, because it can be changed into another prime (26023453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13011716 + 13011717.

It is an arithmetic number, because the mean of its divisors is an integer number (13011717).

Almost surely, 226023433 is an apocalyptic number.

It is an amenable number.

26023433 is a deficient number, since it is larger than the sum of its proper divisors (1).

26023433 is an equidigital number, since it uses as much as digits as its factorization.

26023433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 26023433 is about 5101.3167907904. The cubic root of 26023433 is about 296.3385803348.

Adding to 26023433 its reverse (33432062), we get a palindrome (59455495).

The spelling of 26023433 in words is "twenty-six million, twenty-three thousand, four hundred thirty-three".