Base | Representation |
---|---|
bin | 111011011100011110111100… |
… | …110001000001111000000011 |
3 | 1021021200121210221120021110121 |
4 | 323130132330301001320003 |
5 | 233231431431014303123 |
6 | 2324012504043041111 |
7 | 106032366325631356 |
oct | 7334367461017003 |
9 | 1237617727507417 |
10 | 261442121244163 |
11 | 76337a87729932 |
12 | 253a5299510197 |
13 | b2b5b6a112142 |
14 | 487bc1ab5029d |
15 | 2035a99aea75d |
hex | edc7bcc41e03 |
261442121244163 has 2 divisors, whose sum is σ = 261442121244164. Its totient is φ = 261442121244162.
The previous prime is 261442121244127. The next prime is 261442121244167. The reversal of 261442121244163 is 361442121244162.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 261442121244163 - 229 = 261441584373251 is a prime.
It is not a weakly prime, because it can be changed into another prime (261442121244167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130721060622081 + 130721060622082.
It is an arithmetic number, because the mean of its divisors is an integer number (130721060622082).
Almost surely, 2261442121244163 is an apocalyptic number.
261442121244163 is a deficient number, since it is larger than the sum of its proper divisors (1).
261442121244163 is an equidigital number, since it uses as much as digits as its factorization.
261442121244163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 442368, while the sum is 43.
Subtracting 261442121244163 from its reverse (361442121244162), we obtain a palindrome (99999999999999).
The spelling of 261442121244163 in words is "two hundred sixty-one trillion, four hundred forty-two billion, one hundred twenty-one million, two hundred forty-four thousand, one hundred sixty-three".
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