Base | Representation |
---|---|
bin | 11000011010000111… |
… | …100101100110110001 |
3 | 2111122110222100212201 |
4 | 120122013211212301 |
5 | 412133222003213 |
6 | 20012332223201 |
7 | 1615313220346 |
oct | 303207454661 |
9 | 74573870781 |
10 | 26208000433 |
11 | 1012980769a |
12 | 50b500ab01 |
13 | 261889c384 |
14 | 13a899a7cd |
15 | a35c8d6dd |
hex | 61a1e59b1 |
26208000433 has 2 divisors, whose sum is σ = 26208000434. Its totient is φ = 26208000432.
The previous prime is 26208000397. The next prime is 26208000449. The reversal of 26208000433 is 33400080262.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22509901089 + 3698099344 = 150033^2 + 60812^2 .
It is a cyclic number.
It is not a de Polignac number, because 26208000433 - 217 = 26207869361 is a prime.
It is a super-2 number, since 2×262080004332 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (26208000733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13104000216 + 13104000217.
It is an arithmetic number, because the mean of its divisors is an integer number (13104000217).
Almost surely, 226208000433 is an apocalyptic number.
It is an amenable number.
26208000433 is a deficient number, since it is larger than the sum of its proper divisors (1).
26208000433 is an equidigital number, since it uses as much as digits as its factorization.
26208000433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 26208000433 its reverse (33400080262), we get a palindrome (59608080695).
The spelling of 26208000433 in words is "twenty-six billion, two hundred eight million, four hundred thirty-three", and thus it is an aban number.
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