Base | Representation |
---|---|
bin | 1011111011011100111110… |
… | …00101010011001111001011 |
3 | 10102212202110120100220221111 |
4 | 11331232133011103033023 |
5 | 11414241201231243111 |
6 | 131442455152151151 |
7 | 5345126156042104 |
oct | 575563705231713 |
9 | 112782416326844 |
10 | 26232034243531 |
11 | 83a3a4150aa16 |
12 | 2b37b3b2384b7 |
13 | 118389360178c |
14 | 6698cc7c73ab |
15 | 30754e795a21 |
hex | 17db9f1533cb |
26232034243531 has 2 divisors, whose sum is σ = 26232034243532. Its totient is φ = 26232034243530.
The previous prime is 26232034243447. The next prime is 26232034243559. The reversal of 26232034243531 is 13534243023262.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26232034243531 - 213 = 26232034235339 is a prime.
It is a super-2 number, since 2×262320342435312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (26232034241531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13116017121765 + 13116017121766.
It is an arithmetic number, because the mean of its divisors is an integer number (13116017121766).
Almost surely, 226232034243531 is an apocalyptic number.
26232034243531 is a deficient number, since it is larger than the sum of its proper divisors (1).
26232034243531 is an equidigital number, since it uses as much as digits as its factorization.
26232034243531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 26232034243531 its reverse (13534243023262), we get a palindrome (39766277266793).
The spelling of 26232034243531 in words is "twenty-six trillion, two hundred thirty-two billion, thirty-four million, two hundred forty-three thousand, five hundred thirty-one".
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