Base | Representation |
---|---|
bin | 100110001100110101111… |
… | …100011100111011100001 |
3 | 100021221220211100002112111 |
4 | 212030311330130323201 |
5 | 321002231243314231 |
6 | 5325545035355321 |
7 | 360442112214463 |
oct | 46146574347341 |
9 | 10257824302474 |
10 | 2625130057441 |
11 | 9223475314a1 |
12 | 3649268b2b41 |
13 | 160719663a48 |
14 | 910b2494133 |
15 | 4844415d4b1 |
hex | 26335f1cee1 |
2625130057441 has 2 divisors, whose sum is σ = 2625130057442. Its totient is φ = 2625130057440.
The previous prime is 2625130057421. The next prime is 2625130057463. The reversal of 2625130057441 is 1447500315262.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2133162486225 + 491967571216 = 1460535^2 + 701404^2 .
It is a cyclic number.
It is not a de Polignac number, because 2625130057441 - 213 = 2625130049249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2625130057394 and 2625130057403.
It is not a weakly prime, because it can be changed into another prime (2625130057421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1312565028720 + 1312565028721.
It is an arithmetic number, because the mean of its divisors is an integer number (1312565028721).
Almost surely, 22625130057441 is an apocalyptic number.
It is an amenable number.
2625130057441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2625130057441 is an equidigital number, since it uses as much as digits as its factorization.
2625130057441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 40.
The spelling of 2625130057441 in words is "two trillion, six hundred twenty-five billion, one hundred thirty million, fifty-seven thousand, four hundred forty-one".
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