Base | Representation |
---|---|
bin | 100110010011010111111… |
… | …010100101001010010001 |
3 | 100022122000112101012022211 |
4 | 212103113322211022101 |
5 | 321111111431140103 |
6 | 5333104535232121 |
7 | 361110641420626 |
oct | 46232772451221 |
9 | 10278015335284 |
10 | 2632142443153 |
11 | 925315875693 |
12 | 366163218641 |
13 | 1612963b53c2 |
14 | 9157991634d |
15 | 48704ac236d |
hex | 264d7ea5291 |
2632142443153 has 2 divisors, whose sum is σ = 2632142443154. Its totient is φ = 2632142443152.
The previous prime is 2632142443129. The next prime is 2632142443163. The reversal of 2632142443153 is 3513442412362.
2632142443153 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2020881166929 + 611261276224 = 1421577^2 + 781832^2 .
It is a cyclic number.
It is not a de Polignac number, because 2632142443153 - 25 = 2632142443121 is a prime.
It is not a weakly prime, because it can be changed into another prime (2632142443163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1316071221576 + 1316071221577.
It is an arithmetic number, because the mean of its divisors is an integer number (1316071221577).
Almost surely, 22632142443153 is an apocalyptic number.
It is an amenable number.
2632142443153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2632142443153 is an equidigital number, since it uses as much as digits as its factorization.
2632142443153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 414720, while the sum is 40.
The spelling of 2632142443153 in words is "two trillion, six hundred thirty-two billion, one hundred forty-two million, four hundred forty-three thousand, one hundred fifty-three".
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