Search a number
-
+
26358417560491 is a prime number
BaseRepresentation
bin1011111111001000011000…
…00111011001001110101011
310110022211200102212122010121
411333210030013121032223
511423324014343413431
6132020520113224111
75360222105362042
oct577441407311653
9113284612778117
1026358417560491
1184425a66065a5
122b58530862037
131192785104773
14671a7b7dd559
1530a999d4e611
hex17f90c1d93ab

26358417560491 has 2 divisors, whose sum is σ = 26358417560492. Its totient is φ = 26358417560490.

The previous prime is 26358417560393. The next prime is 26358417560513. The reversal of 26358417560491 is 19406571485362.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-26358417560491 is a prime.

It is a super-2 number, since 2×263584175604912 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (26358417260491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13179208780245 + 13179208780246.

It is an arithmetic number, because the mean of its divisors is an integer number (13179208780246).

It is a 1-persistent number, because it is pandigital, but 2⋅26358417560491 = 52716835120982 is not.

Almost surely, 226358417560491 is an apocalyptic number.

26358417560491 is a deficient number, since it is larger than the sum of its proper divisors (1).

26358417560491 is an equidigital number, since it uses as much as digits as its factorization.

26358417560491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43545600, while the sum is 61.

The spelling of 26358417560491 in words is "twenty-six trillion, three hundred fifty-eight billion, four hundred seventeen million, five hundred sixty thousand, four hundred ninety-one".