Base | Representation |
---|---|
bin | 1011111111001000011000… |
… | …00111011001001110101011 |
3 | 10110022211200102212122010121 |
4 | 11333210030013121032223 |
5 | 11423324014343413431 |
6 | 132020520113224111 |
7 | 5360222105362042 |
oct | 577441407311653 |
9 | 113284612778117 |
10 | 26358417560491 |
11 | 84425a66065a5 |
12 | 2b58530862037 |
13 | 1192785104773 |
14 | 671a7b7dd559 |
15 | 30a999d4e611 |
hex | 17f90c1d93ab |
26358417560491 has 2 divisors, whose sum is σ = 26358417560492. Its totient is φ = 26358417560490.
The previous prime is 26358417560393. The next prime is 26358417560513. The reversal of 26358417560491 is 19406571485362.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-26358417560491 is a prime.
It is a super-2 number, since 2×263584175604912 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (26358417260491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13179208780245 + 13179208780246.
It is an arithmetic number, because the mean of its divisors is an integer number (13179208780246).
It is a 1-persistent number, because it is pandigital, but 2⋅26358417560491 = 52716835120982 is not.
Almost surely, 226358417560491 is an apocalyptic number.
26358417560491 is a deficient number, since it is larger than the sum of its proper divisors (1).
26358417560491 is an equidigital number, since it uses as much as digits as its factorization.
26358417560491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43545600, while the sum is 61.
The spelling of 26358417560491 in words is "twenty-six trillion, three hundred fifty-eight billion, four hundred seventeen million, five hundred sixty thousand, four hundred ninety-one".
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